What is the normality of 25.0 g of Al(OH)3 dissolved in 100.0 mL of water?
"Molarity= \\dfrac{\\dfrac{25}{78}}{0.1}"
= 3.20M
Hence, Normality= "n\\times Molarity"
"3\\times 3.20 = 9.60"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment