Answer to Question #193182 in General Chemistry for Natalie

Question #193182

In the reaction: 3H2SO4 + 2Al(OH)3 → Al2 (SO4)3 + 6H2O,

If 25.0 g of sulfuric acid reacts with 20.8 g of aluminum hydroxide,

a) Which is the limiting reactant?

b) Determine the mass of excess reactant remaining.

c) Determine the mass of each product formed.


1
Expert's answer
2021-05-14T02:35:16-0400

Moles of sulfuric acid =


Moles of aluminium hydroxide =


limiting reactant is aluminium hydroxide



= 3 × 0.25 = 0.75


Mass = 0.75 × 18 =13.5 grams



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