In the reaction: 3H2SO4 + 2Al(OH)3 → Al2 (SO4)3 + 6H2O,
If 25.0 g of sulfuric acid reacts with 20.8 g of aluminum hydroxide,
a) Which is the limiting reactant?
b) Determine the mass of excess reactant remaining.
c) Determine the mass of each product formed.
Moles of sulfuric acid =
Moles of aluminium hydroxide =
limiting reactant is aluminium hydroxide
= 3 × 0.25 = 0.75
Mass = 0.75 × 18 =13.5 grams