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# Answer to Question #192947 in General Chemistry for sdoog23

Question #192947

Calculate the heat of hydrogenation of ethane πΆ2π»4 using the following reactions:

2πΆ (ππππβππ‘π) + 3π»2 (π) β πΆ2π»6 (π) βπ»π = β84.5 ππ½/πππ

2πΆ(ππππβππ‘π) + 2π»2 (π) β πΆ2π»4 (π) βπ»π = 52.3 ππ½/mol

1
Expert's answer
2021-05-14T02:34:40-0400

Reaction of heat of hydrogenation of ethane:

"C_2H_4+H_2\\Rightarrow C_2H_6"

Given that:

Equation .1.

"2C+3H_2\\Rightarrow C_2H_6:\\Delta H_1=-84.5KJ\/mol"

Equation .2.

"2C+2H_2\\Rightarrow C_2H_4:\\Delta H_2=" "52.3KJ\/mol"

Now to form the main equation we have to subtract equation 2 from equation 1:

So heat of hydrogenation"=" "\\Delta H_1-\\Delta H_2"

"=-84.5-52.3=-136.8KJ\/mol"

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Assignment Expert
21.06.21, 13:53

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Stephany
21.06.21, 12:12

Thank you for the answer it helps of me

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