Question #192839

The pressure of a gas is reduced from 1200.0 mm Hg to 850.0 mm Hg as the volume of its container is increased by moving a piston from 85.0 mL to 350.0 milliliters. What would the final temperature be if the original temperature were 90.0 °C?

Expert's answer

"\\frac{P_1V_1}{T_1}=\\frac{P_2V_2}{T_2}"

"\\frac{1200\u00d785.0}{363}=\\frac{850\u00d7350}{T_2}"

"T_2= 1058.75K=785.75\u00b0C"

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