Answer to Question #192697 in General Chemistry for Richard

Question #192697

To neutralize 100 g of HNO3 solution, 30 cm3 of 15% NaOH solution with a density of 1.15 g / cm3 was used. Calculate the mass fraction (in%) of nitric acid in the solution!


1
Expert's answer
2021-05-13T02:09:25-0400

15% of NaOH means

In 100g solution 15g of NaOH

d = m/v

v = m/d = 100/1.15 = 86.95mL

Molarity of NaOH =

=4.31 M

moles of NaOH required = 4.31×

= 0.129moles

moles of HNO3 needed = 0.129 moles

= 0.129

mass = 0.129 × molar mass

mass = 0.129×63 = 8.127g

mass fraction = = 8.127 %


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