Answer to Question #192534 in General Chemistry for kyla

Question #192534

If you add 40. mL of water to a beaker which contains 20. mL of a 5.0 M solution, what will be the new concentration?


1
Expert's answer
2021-05-14T02:34:23-0400

C=m/M*V

n(solution)=40ml/22.4l/mol=1.8mol

m(solution)=1.8mol*18g/mol=32.4g

C=32.4g/5M*(20l+40l)=0,108M



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