Answer to Question #192500 in General Chemistry for lara

Question #192500

Use the following information: A container has 8360.0 torr of Nitrogen, 5.000 atm of Oxygen, 101.3 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.


What is the mole fraction of Carbon Dioxide?


A. 0.0556

B. 0.0670

C. 0.2567

D. 0.6676

E. 0.7572


1
Expert's answer
2021-05-14T02:35:47-0400

8360 torr x 1 atm/760 torr = 11 atm N2

5 atm O2

101.1 kPa x 1 atm/101.32 = 0.998 atm CO2

760 mm Hg x 1 atm/760 mm Hg = 1 atm

Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm

mole fraction N2 = 1.1 atm/17.998


D.) 0.6676

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Comments

Assignment Expert
17.05.21, 11:24

Dear Lara please post a new task


Assignment Expert
17.05.21, 11:24

Dear lara,

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lara
15.05.21, 02:12

Use the following information: A container has 8360.0 torr of Nitrogen, 5.000 atm of Oxygen, 101.3 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide. What is the mole fraction of Oxygen? A. 0.1673 B. 0.2670 C. 0.2778 D. 0.4675 E. 0.5782

lara
14.05.21, 15:44

thank you!

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