Question #192352

Use the following information: A container has 8360.0 torr of Nitrogen, 5.00 atm of Oxygen, 101.1 kPa of Argon, and 760.0 mm Hg of Carbon Dioxide.

What is the mole fraction of Carbon Dioxide?

A. 0.0556

B. 0.0670

C. 0.2567

D. 0.6676

E. 0.7572

Expert's answer

= 11 atm N2

5 atm O2

= 0.998 atm Ar

= 1 atm CO2

Total Pressure = 11 atm + 5 atm + 0.998 atm +1 atm = 17.998 atm

mole fraction =

Mole fraction of Carbon Dioxide= **0.278**

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