Question #191748

What is the molarity of a HCl solution if it takes 15.6 mL of a 1.00 M NaOH solution toÂ titrate 25.0 mL of the acid to a neutral endpoint?

Expert's answer

Molarity of "HCl" can be calculated as,

"\\dfrac{x \\hspace{2mm}mol \\hspace{2mm}of\\hspace{2mm} HCl}{1L \\hspace{2mm}of\\hspace{2mm} HCl\\hspace{2mm} solution} = \\dfrac{25}{15.6}(\\dfrac{10^3}{1L})(\\dfrac{0.115\\hspace{2mm}mol\\hspace{2mm} NaOH}{10^3\\hspace{2mm}mL\\hspace{2mm} NaOH\\hspace{2mm}solution})(\\dfrac{1 mol\\hspace{2mm} HNO_3}{1 mol\\hspace{2mm} NaOH})"

From this equation we can calculate the molarity of "HCl" .

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