Answer to Question #191707 in General Chemistry for Ayame

Question #191707

240 mL of 0.32 M aluminum chloride reacts with excess silver nitrate in a double displacement reaction. What mass of silver chloride precipitate is produced?


AlCl3 + 3 AgNO3 -> Al(NO3)3 + 3 AgCl

1
Expert's answer
2021-05-12T06:30:29-0400

The reaction is


The moles of Aluminium chloride =




moles


Now according to the symmetry of the equation:


1 mole of Aluminium chloride gave 3 moles of silver chloride

Hence 0.077 moles of Aluminium chloride gave moles of silver chloride.


Now mass of silver chloride =moles of silver chloride molar mass of silver chloride

= gm


So 33.10 gm of silver chloride is precipitated in produced after the reaction.








Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS