Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 3.28 g of hydrochloric acid is mixed with 2.2 g of sodium hydroxide. Calculate the maximum mass of Sodium Chloride that could be produced by the chemical reaction. Round your answer to 2 significant digits.
given reaction is-
moles of HCl taken =
moles of NaOH taken
So NaOH is the limiting reagent here
mass of Nacl formed = moles of Nacl multiplied by its molar mass
Moles of Nacl will be equal to moles of NaOH taken as they react in the ratio of 1:1.