By titration it is found that 114.3 mL of 0.562 M NaOH is needed to titrate 48.0 mL of HCl. What is the concentration of the HCl in molarity?
: NaOH +HCl ⇒NaCl + H2O.
So the ratio between the reactants is 1:1.
The moles of NaOH needed to neutralize the acid = volume of NaOH solution × concentration of NaOH solution
Moles of NaoH
Therefore 0.0642 mole of HCl is presented in the acid solution.
The concentration of HCl solution = moles of HCl/volume of HCl solution
Concentration of HCL