Question

A student is attempting to make up 500.0 mL of a 0.433 M solution of Li₃PO₄ from a stock solution which has a molarity of 1.70 M. How many mL of the stock solution will they need to add to a 500.0 mL volumetric flask to make up the 0.433 M solution?

Answer 1

$Moles = 0.433×0.5=0.2165$

$Volume=\frac{0.2165}{1.70}=0.1273l=127.3ml$