Question #191154

How much heat, in joules, is absorbed by 500.0 g of water as its temperature is increased from 10.0oC to 85.0oC? The specific heat of water is 4.184 J/g•oC

Expert's answer

We know the formula,

"Q= nC_v \\Delta T"

"Q = \\dfrac{500}{18} \\times 4.184 \\times (85-10)"

"Q = 8716.66J"

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