Question #190622

For the reaction

2NH

3

(g)↽−

−⇀

3H

2

(g)+N

2

(g)

2NH3(g)↽−−⇀ 3H2(g)+N2(g)

the equilibrium concentrations were found to be [NH

3

]=0.250 M

[NH3]=0.250 M, [H

2

]=0.450 M

[H2]=0.450 M, and [N

2

]=0.800 M

[N2]=0.800 M. What is the equilibrium constant for this reaction?

Expert's answer

Ans:-

Reaction is

"2\u2062NH_3\u2062(g)\u2062\\iff 3\u2062H_2\u2061(g)+N_2\u2061(g)"

We have "[NH_3]=0.250 M" "[H_2]=0.450 M" "[N_2]=0.800 M"

"\\Rightarrow" Equilibrium constant ("K")"=\\dfrac{[H_2]^3\\times[N_2]}{[NH_3]^2}"

"\\Rightarrow" Equilibrium constant ("K")="\\dfrac{(0.450)^3\\times(0.800)}{(0.250)^2}=1.1664"

"\\therefore" Equilibrium constant ("K")="1.1664"

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