Answer to Question #190468 in General Chemistry for Kennedy

Question

Copper sulphate solution is electolysed using platinum electrodes A. current of 0.193 amperes is passed for 3hrs. How many grams of copper are deposited? (cu = 63.5, F = 96500 coulombs)

Answer 1

Time = $2hrs. = 120 \times 60 = 7200s$

Current $= 0.193A$

Quantity of electricity $= 120 \times 0.193 = 60 \times 23.16$

96,500 deposits 63.5 gm of Cu.

60 x 23.2 will deposit $\dfrac{63.5 \times 60 \times 23.2 }{96500} = 0.457g$ of Copper.