Question #190071

What mass of silver nitrate AgNo3, is needed to make 0.50L of a 0.10mol/L solution?

Expert's answer

Let "x" be number of moles in 0.50L of solution , to find the value of "x" molarity of both the solution will be same "\\ 0.10=\\dfrac{x}{0.50}" ,"\\ x=0.05\\ mol"

Now you can calculate mass of silver nitrate , n = "\\dfrac{m}{Mw}" , Where n = number of moles

m = mass

Mw = molecular weight = Molecular weight of "AgNO_3=169.87\\ MW"

"m=n\\times Mw=" 169.87"\\times0.05=" 8.4935 g

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