Answer to Question #189333 in General Chemistry for Sheru

Question

An aqueous solution of ferric hydroxide has a specific gravity of 1.25 and a weight fraction of

solute equal to 0.10. Calculate:

a) % solute by mole

b) Molality of the solution

c) Normality of the solution

d) ppb of solute

Answer 1

i) Moles of Fe(OH)2=$0.093moles$

ii)Molarity of the Solution =$1.03M$

iii)Normality of the solution=$3.5M$

iv)ppb of solute=$10^{5} PPm$