Answer to Question #189234 in General Chemistry for John taylor

General Chemistry

Question #189234

What is the pH if the [OH^-] is 3.99*10^-12

Expert's answer

POH = -log [OH-]

POH = -log 3.99*10^-12

POH = 11.4

But PH + POH = 14

∴ PH = 14 - POH

PH = 14 - 11.4

PH = 2.6

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