Question #189101

Using the unbalanced equation above calculate the moles of hydrogen iodide vapor produced by 2.8 moles of iodine vapor.

_H2(g) + _l2(g) > _Hl (g)

Expert's answer

**# Using unbalanced chemical equation :**

The reaction is :

"H_2+I_2\\Rightarrow HI"

According to the equation:

1 mole of iodide vapor gave 1 mole of Hydrogen iodide

Hence 2.8 mole of iodide vapor gave 2.8 moles of Hydrogen iodide.

So the answer is 2.8 mole of Hydrogen iodide,if the equation is unbalanced.

**# Using balanced chemical equation :**

If we balance the equation then it becomes

"H_2+I_2 \\Rightarrow2HI"

Here in this case:

1 mole of iodide vapor gave 2 mole of Hydrogen iodide

Hence 2.8 mole of iodide vapor gave 2.8"\\times2=5.6" moles of Hydrogen iodide.

So the answer is 5.6 mole of Hydrogen iodide,if the equation is balanced.

Thank you...

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