Answer to Question #189101 in General Chemistry for Tyler Drotning

Question #189101

Using the unbalanced equation above calculate the moles of hydrogen iodide vapor produced by 2.8 moles of iodine vapor.


_H2(g) + _l2(g) > _Hl (g)


1
Expert's answer
2021-05-10T01:50:22-0400

# Using unbalanced chemical equation :


The reaction is :

According to the equation:

1 mole of iodide vapor gave 1 mole of Hydrogen iodide

Hence 2.8 mole of iodide vapor gave 2.8 moles of Hydrogen iodide.


So the answer is 2.8 mole of Hydrogen iodide,if the equation is unbalanced.


# Using balanced chemical equation :


If we balance the equation then it becomes

Here in this case:

1 mole of iodide vapor gave 2 mole of Hydrogen iodide

Hence 2.8 mole of iodide vapor gave 2.8 moles of Hydrogen iodide.


So the answer is 5.6 mole of Hydrogen iodide,if the equation is balanced.



Thank you...




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