What is the pH solution containing 0.30 M HCOOH and 0.52 M HCOOK?
HCOOH(aq) + H2O(l) = H3O+(aq) + HCOO-(aq)
pKa = 3.77
pH = pKa + log ( [HCOO−][HCOOH]\frac{[HCOO^-]}{[HCOOH]}[HCOOH][HCOO−] )
pH = 3.77 + log ( [0.52][0.30]\frac{[0.52]}{[0.30]}[0.30][0.52] )
pH = 4.01
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