Answer to Question #188368 in General Chemistry for joshua

Question #188368

1.20g Sb reacts with 2.40g of I 2 :

Expert's answer

2Sb + 3I₂ → 2SbI₃

Mole ratio 2:3 which implies 2 mols of Sb reacts with 3 moles of I to yield 2 moles of SbI3.

1.2+ 2.4= 3.6g of SbI3 produced

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