Answer to Question #187416 in General Chemistry for reaction stoichiometry

Question

1.  How many moles of magnesium are required to react with 36.70 moles of hydrochloric acid? 

Moles-Moles

The balanced equation for this reaction is:       Mg + 2HCl   →   MgCl2 +    H2       

2.  If 6.0 l moles of water, H2O, were formed during this reaction, how many grams of barium oxide, BaO, were used? 

moles-moles-Grams

Balanced Chemical Equation:     BaO (s)  +  H2SO4 (aq) →  BaSO4 (s) +     H2O (g)

 

 

3.  What mass of sodium chloride is produced when chlorine reacts with 3.65 grams of sodium 

iodide according to the balanced equation:      2NaI  +   Cl2   →    2NaCl  +     I2 

Grams-moles-moles-grams

4.  How many grams of Fe2O3 will be produced if 0.18 grams of Fe reacts? 

     The UNBALANCED equation for this reaction is:    4Fe + 3O2 → 2Fe2O3

Answer 1

1. Ratio is 2HCl : 1 Mg

= 36.70/2

= 18.35 moles

2.mole ratio is 1:1

= 6 moles of BaO

Molar Mass of BaO = 153.33 g

= 153.33g

3. mole ratio is 2:2

Molar Mass of sodium Iodide = 149.89

3.65/149.89

= 0.0244

Molar Mass of sodium chloride = 58.44

= 0.0244 × 58.44

= 1.4231g