Question

By the addition of water, 40.0 mL of 8.0 M H₂SO₄ is diluted to 160.0 mL. What is the molarity after dilution?

Answer 1

$(MV)_{before dilution} = (MV)_{after dilution}$

40 mL of a 8M solution of $H_2SO_4$ is diluted to a final volume of $160mL$ .

Hence, After applying the above formula

We get,

$40 \times 8 = M \times 160$

$M = 32$