Question

A balloon has a volume of 13.7 L at 34.0 ºC. What would be the volume of the balloon at –12.0 ºC?

Answer 1

From Charles law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{13.7}{307}= \frac{V_2}{261}$

$V_1=\frac{13.7×261}{307}= 11.65 L$