What is K
sp
for the following equilibrium if lithium phosphate has a molar solubility of 9.7×10
−4
M
?
Li
3
PO
4
(s)↽−
−⇀
3Li
+
(aq)+PO
3−
(aq)
Ksp = (3x)3 (4x)4 = 12x12
= 12 ( 9.7 x 10-4)12 = 3.33 x 10-36
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