Calculate [h3o+] at 25 grades celsius when [oh-]=2.5 x 10 ^-9M
"[H_3O^{+}]=\\frac {K_w} {[OH^-] }"
"[H_3O^+]=\\frac {1.0\u00d710 ^{-14}}{2.5\u00d710 ^{-9}}"
"[H_3O^+]=4.0\u00d710 ^{-6}M"
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