Answer to Question #186111 in General Chemistry for Adam LAquis

Question #186111

Cyanic acid is a weak monoprotic acid. If the pH of 0.150 M cyanic acid is 2.32.Calculate Ka for cyanic acid.



1
Expert's answer
2021-04-27T07:49:20-0400

"pH=2.32"


"pH=-log([H_3O^+])"


"log([H_3O^+])=-pH"


"10^{log([H_3O^+])}=10^{-pH}"


"([H_3O^+])=10^{-pH}"


"([H_3O^+])=10^{-2.32}=4.8\u00d710^{-3}M"


"[A^-]=([H_3O^+])" Produced in 1:1 mole


"[A^-]=4.8\u00d710^{-3}M"


"HA=0.150-[4.8\u00d710^{-3}]"


"HA=0.1452M"



"K_a=\\frac{[A^- ]\u00d7 [H_3O^+]}{[HA]}"


"K_a=\\frac {[4.8\u00d710^{-3}]^2}{0.1452}"


"K_a= 1.6 \u00d710^{-4}M"




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