Answer to Question #185453 in General Chemistry for sda

Question

 Show all work out and answer questions a, b,and c!

The Y^- ion reacts with water to form HY and hydroxide ion, as shown in the following equation.

Y^- (aq) + H2O (l) ⇌ HY (aq) + OH^- (aq)

Given that [OH^-] is 1.77 x 10^-5 M in a 0.480 M solution of NaY, calculate each of the following:

(a) The value of K_b for the Y^- ion. 

(b) The value of K_a for HY. 

(c) Which acid, HZ or HY, is stronger? Justify your answer

Answer 1

$K_b =\frac{ K_w} {K_a}$

$K_b =\frac{ 1.77 × 10^{-5}}{0.480}=3.7×10^{-5}$