Answer to Question #184156 in General Chemistry for JIO

Question #184156

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A weak acid, HZ, has a Ka value of 6.52 x 10-5.

(a) Write the reaction of HZ with water. 

(b) Write the equilibrium expression for the reaction of HZ with water.

(c) Calculate the pH of a 0.150 M solution of HZ. 

(d) The Y- ion reacts with water to form HY and hydroxide ion, as shown in the following equation.

Y- (aq) + H2O (l) ⇌ HY (aq) + OH- (aq)

Given that [OH-] is 1.77 x 10-5 M in a 0.480 M solution of NaY, calculate each of the following:

(i) The value of Kb for the Y- ion. 

(ii) The value of Ka for HY. 

(e) Which acid, HZ or HY, is stronger? Justify your answer


1
Expert's answer
2021-04-25T03:50:07-0400

a).

"HZ + H_2O ==> H3O^+ + Z^-"


b)

"HZ_{aq} + H2O_ {l} \u21cc H3O^+_{aq}+ Z^- _{aq}" "K_a = 2.9 \u00d7 10^{-8}"


PH = -log(0.150)

PH = 0.8



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