Sulfur Dioxide reacts with Oxygen gas to form Sulfur Trioxide
A. If 3.4 moles of Sulfur Diocide reacts with excess Oxygen gas, how many moles of Sulfur Trioxide will form?
B. How many moles of Oxygen gas will react completely with 4.7 moles of Sulfur Dioxide?
2 SO2 (g) + O2 (g) --> 2 SO3
A. 3.4 moles of SO2
2 moles of SO2 = 2 moles of SO3
= 3.4 moles of SO3
B. 2 moles of SO2 react with 1 mole of O2
= 4.7 moles of SO2 = 4.7/2
= 2.35moles of O2