Question

A standard airbag has 130.0 g of sodium azide (NaN3).  How many grams of dangerous sodium metal would be produced? 

Show your stoichiometry work in the tables below, including all appropriate units, for full credit. 

Answer 1

The decomposition of NaN3 is represented by the following equation:

2NaN₃ --> 2Na + 3N₂

Therefore,

$m(Na)=130.0g(NaN_3)\times\frac{1mol(NaN_3)}{65.01g(NaN_3)}\times\frac{2mol(Na)}{2mol(NaN_3)}\times\frac{22.99g(Na)}{1mol(Na)}=45.97g$

Answer: 45.97 g