Answer to Question #183786 in General Chemistry for hanna

Question #183786

calculate and describe how to make 20ml of 0.06M HCL starting with 6.0M HCL and water.


1
Expert's answer
2021-04-21T03:54:18-0400

Given C1 = 6.0 M, C2 = 0.06 M, and V2 = 20 mL. The initial volume is unknown (V1).

"C_1V_1=C_2V_2"

Therefore,

"V_1=\\frac{C_2V_2}{C_1}=\\frac{0.06M\\times20mL}{6.0M}=0.2mL"

To make the required solution, 0.2 mL of the 6.0 M HCl should be carefully measured and transferred to a volumetric flask, and then diluted with distilled water to the 20 mL mark.


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