# Answer to Question #183783 in General Chemistry for Keke

Question #183783

Application

1. Hydrogen gas can easily be generated using the reaction of magnesium with hydrochloride acid HCL,for a reaction, 500ml of hydrogen gas was collected by water displacement. Calculate the mass of magnesium required to produce "dry" hydrogen gas a total pressure of 125 kPa and 22°C?

2. Large quantities of methane gas are being released from arctic waters as water temperature rise due to global warming. A methane bubble has a volume of 2000L at 10 atm of pressure and 4.0°C. What will the volume of the bubble be at 10°C and 102 kPa

3. Carbon dioxide in high levels can cause death. One method of removing carbon dioxide from the air of enclosed compartments involves this reaction

2NaOH + CO2 (g) = Na2CO (s) + H2O (l)

What mass of sodium hydroxide is required to remove all the carbon dioxide in the air over a 5 hr period, if the volume of CO2 produced is 1.25L/hr at a temperature of 22°C And a pressure of 101.8kPa?

1
2021-05-12T06:29:16-0400

1.

"Mg+ 2HCl \\to MgCl_2+ H_2"

"PV = nRT\\\\\n125000\u00d7500\u00d710^{-6}= n\u00d78.314\u00d7(273.15+22)"

"62.5 = 2453.88n"

"n = \\dfrac{62.5}{2453.88}= 0.0255\\ moles"

mass of hydrogen = 0.0255 mol × 2g/mol = 0.051g

2.

"\\dfrac{P_1V_1}{T_1}=\\dfrac{P_2V_2}{T_2}"

"\\dfrac{10\u00d7102\u00d72000}{277}=\\dfrac{102\u00d7V_2}{283}"

"V_2 =\\dfrac{283\u00d710\u00d72000}{277}=20433.21\\ L"

3.

"2NaOH + CO_2 \\to Na_2CO + H_2O"

Volume of CO2 produced over 5 hours is 6.25L

"PV = nRT\\\\\n101800\u00d7 6.25\u00d7 10^{-3} = n\u00d78.314\u00d7 (273+22)\\\\\n636.25 = 2452.63n"

"n = \\dfrac{636.25}{2452.63}= 0.26\\ moles"

According to the reaction above,

0.26 moles of CO2 requires 0.52 moles of NaOH to go into completion.

mass of NaOH required = 0.52 moles × 40 g/mol = 20.8g

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!