8.0 mL of 0.10 M HC2H3O2 is titrated with 0.10 M NaOH. Perform the following calculations
pH of the acid before any NaOH is addedi is
"pH = -log (0.10)=1"
Volume of 0.10 M NaOH needed to reach the equivalence point= 0.04398 L0.04398L
"pH = 7.00"
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