Answer to Question #183527 in General Chemistry for Valeria Viel Medina

General Chemistry

Question #183527

Oxigen atoms in 4.90 mol in Al₂O₃

Expert's answer

1 mole Al2O3 contains 2 moles of Al and 3 moles of O.

= 3/5 × 4.90

= 2.94 moles

1 mole = 6.02 × 10²³

= 2.94 × 6.02 × 10²³

= 1.7699 × 10²⁴atoms

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