Answer to Question #183183 in General Chemistry for dad

Question #183183

8.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. Perform the following calculations with all workout shown


pH of the acid before any NaOH is added

Volume of 0.10 M NaOH needed to reach the equivalence point

pH at the equivalence point


1
Expert's answer
2021-04-23T07:32:14-0400

"PH=- log [H^+]"


"PH=-log[0.10]=1"


NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l)


Volume of NaOH = 8.0 ml




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