8.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. Perform the following calculations with all workout shown
pH of the acid before any NaOH is added
Volume of 0.10 M NaOH needed to reach the equivalence point
pH at the equivalence point
"PH=- log [H^+]"
Volume of NaOH = 8.0 ml