How many grams of glucose (c6h12o6) would you need to prepare 2.0 L of 2% glucose solution (M/V)?show your solution.
2% (m/v) glucose solution means: 2.0g(glucose)100mL(solution)\frac{2.0g (glucose)}{100mL (solution)}100mL(solution)2.0g(glucose)
?g glucose = 2.0L soln
?g(glucose)=2.0×2100=0.04Kg=40g?g(glucose) = 2.0 × \frac{2}{100}=0.04 Kg = 40g?g(glucose)=2.0×1002=0.04Kg=40g
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