Answer to Question #182592 in General Chemistry for Braimah Suraji

General Chemistry

Question #182592

How many mL of 0.1M HNO3 are required to neutralize exactly half of the OH-ions present in 520mL of 0.18N KOH?

Expert's answer

HNO3 + KOH = KNO3 + H2O

0.18 x 520/2 x 0.1 = 468 ml

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. what is the PH of a solution prepared by adding 0.2g of Na2CO3 and o.2g of NaHCO3 to water and bring
2. (a)Describe the preparation of 500mL of 0.08M acetate buffer (pH=5.4) from acetic acid [F.W.=60.05,
3. A solution of 100.00mL of 0.200mol/L sodium carbonate and 200.00 of 0.1000are mixed. What is the mas
4. At 25°C, the vapor pressure of benzene, C6H6, is 95 torr, snd toluene, C7H8, is 28 torr. Find the t
5. What mass of mass of maltose, C12H22O11 is dissolved in 725 mL of 0.118 M maltose solution? Atomic m
6. Illustrate the phase diagram of a substance given with the following points: a triple point at 0.70
7. explain in detail on how nucleotides involved in information transfer and storage in the cells. 20