Answer to Question #182592 in General Chemistry for Braimah Suraji

Question #182592

How many mL of 0.1M HNO3 are required to neutralize exactly half of the OH-ions present in 520mL of 0.18N KOH?


1
Expert's answer
2021-04-19T05:11:24-0400

HNO3 + KOH = KNO3 + H2O

0.18 x 520/2 x 0.1 = 468 ml


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