Answer to Question #182178 in General Chemistry for —-

Question

How many moles of CO₂ are produced when 3.00 g of C₃H₅O₉N₃ decomposes?

Answer 1

The reaction goes as$4C_3H_5O_9N_3\Rightarrow 12CO_2+6N_2+10H_2O+O_2$

From the above reaction we have seen that $4$ mole of $C_3H_5O_9N_3$ produce $12$ mole of $CO_2$

So $1$ mole of $C_3H_5O_9N_3$ produce $3$ mole of $CO_2$

Molar mass of $C_3H_5O_9N_3$ is $227 g/mol$

Moles of $C_3H_5O_9N_3$ $=\dfrac{3}{227}=0.0132 mol$

$0.0132$ mol of $C_3H_5O_9N_3$ produce $0.0132\times3=0.0396 mol$ of $CO_2$