Answer to Question #182176 in General Chemistry for Sophia Zheng

Question

If the [H+] of a solution is 5.7 x 10^-14 , what is the [OH-]? Round to four decimal places.

Answer 1

$Kw=[H+][OH-]$

$Where Kw=1\times 10^{-14}$

Therefore:

$OH- =\frac{Kw}{H+}$

$OH- = \frac{1\times 10^{-14}}{5.7\times10^{-14}}=0.1754$