Answer to Question #182116 in General Chemistry for Lauren Barad

Question

A sample of Cu with a mass 3.3g is cooled from 53.0^oC to 28.4^oC If the specific heat of Cu is 0.4 ^J/_gC how much energy was applied to the sample?

Answer 1

 Q=mcΔT.

Where

Q=heat energy

m=mass =3.3g

c=specific heat capacity = 0.4J/g

ΔT=change in temperature =(53-28.4)=24.6

$Q=3.3\times0.4\times24.6 =32.472J$