Question

A researcher needs a 0.8750 M solution of potassium hydroxide. The solution will have a final volume of 500.0 mL. How many grams of potassium hydroxide must be added before the container is filled to its final volume?

Answer 1

$Moles$ $(KOH)=\frac {500}{1000}×0.8750= 0.4375moles$

Mass (KOH)$= 56×0.4375=24.5grams$