How many grams of O2 are required to produce 358.5 grams of ZnO?
2Zn + O2 --> 2ZnO
Moles of "Zno" "=\\frac{358.5}{81.38}=4.41moles"
Moles of "O_2=\\frac{4.41}{2}=2.205 moles"
Mass of "O_2= 2.205\u00d716= 35.28g"
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