Answer to Question #181196 in General Chemistry for Err

General Chemistry

Question #181196

What is the pOH of a solution where the [OH-] is 7.3 x 10-2 M?

Expert's answer

POH = -log (OH^-)

= -log(7.3 ×10^-2)

= 1.14

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Name the following compound -Kf₈Nb₆. Single line text.
2. blood that enters the right atrium is ——because it comes from ——?
3. How many moles of LiF would be require to produce a 1.75 M solution with a 875 m volume?
4. A student starts with s 18.0 M solution of H2SO4. How many ml would be required to produce 235 ml of
5. If 545 ml of a 4.50 M solution of HCl was used to prepare a 1.45 L solution of dilute HCl, calculate
6. How many grams of Strontium (II) nitrate are require to produce .250 liters of a 1.25 M solution?
7. How many grams of CaCl2 would be required to produce a .750 M solution with a 855 ml volume?