Answer to Question #181164 in General Chemistry for Ally

General Chemistry

Question #181164

How many grams of Strontium (II) nitrate are require to produce .250 liters of a 1.25 M solution?

Expert's answer

Moles = M × V(L)

= 1.25 × 0.250

=0.3125 mol

Mass = moles × MM

= 0.3125 × 211.6

= [66.1] g

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