Answer to Question #181104 in General Chemistry for Anna Smith

Question

Zinc and hydrochloric acid react according to the following balanced equation:

Zn_(s)  +  2 HCl_(aq)  -->  ZnCl_2(aq)  +  H_2(g)

 

What volume of 0.19 M hydrochloric acid in liters will react with 24.5 grams of zinc?

Answer 1

24.5 g of zn = (24.5/65)=0.37mole of Zn , atomic mass of Zn is 65g/mole , 1 mole Zn react with 2mole HCl , 0.37 mole Zn react with 0.74 mole of HCl,now 0.19(M) HCl solution means ,0.19mole HCl present in 1000mL solution,so 0.74 mole HCl present in 140.6mL solution, hence 140.6mL of 0.19(M) solution required