Question #180868

The proof of an alcoholic beverage is twice the volume percent of ethyl alcohol, C2H5OH. For an 80.0 proof rum, what is the molality of ethyl alcohol if D C2H5OH = 0.789g/ml and MM = 46.08 g/mol.



1
Expert's answer
2021-04-19T05:08:56-0400

Moles = 0.789×46.08=36.36moles0.789×46.08=36.36moles


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