Answer to Question #180183 in General Chemistry for hayley samantha farah

Question

Use the following balanced equation to answer the parts below:

3H2​ + N2 ​ 2NH3

How many grams of NH₃ can be made from 5.60  mol of H₂ and excess N₂?

How many grams of NH₃ can be made from 4.34 mol of N₂ and excess H₂?

If you want to make 19.59 mol of NH₃, how many grams of N₂ do you need?

Answer 1

Molar Mass of NH₃ = 17.03

Molar Mass of N₂ = 28.0134

Molar Mass of H₂ = 2.016

How many grams of NH₃ can be made from 5.60  mol of H₂ and excess N₂?

From the equation

= 3/4×5.6 = 4.2moles of H₂

= 1/4 × 5.6 = 1.4 moles of N₂

3moles of H₂ = 2 moles of NH₃

2/3 × 4.2 = 2.8 moles of NH₃

= 2.8 × 17.031 = 47.6868g

1 mole of N₂ = 2 moles of NH₃

= 1.4 × 2 = 2.8 × 17.031= 47.6868g

= 47.6868 + 47.6868 = 95.3736g of NH₃

How many grams of NH₃ can be made from 4.34 mol of N₂ and excess H₂?

= 3/4×4.34 = 3.255 moles

1/4×4.34 = 1.085moles

= 2/3×3.255 = 2.17 moles of NH₃

= 2.17×17.031 = 36.95727g

1.085 × 2 = 2.17

= 36.95727g

= 36.95727×2 = 73.9145g of NH₃

If you want to make 19.59 mol of NH₃, how many grams of N₂ do you need?

19.59 moles of NH₃

2 moles of NH₃ = 1mole of N₂

= 19.59/2 = 9.795× 28.0134

= 274.391253g of N₂