Answer to Question #179788 in General Chemistry for Lester Salguera

Question #179788

How many liters of solution are needed to make a 1.66 M solution containing 333.44 grams of KMnO4?

Expert's answer

C=n/V

V=n/C

n=m/M

M=39+55+4*16=158(g/mol)

n=333.44/158=2.11(mol)

V=2.11/1.66=1.27(L)

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